College

Limestone has a density of 2.72 g/cm\(^3\). What is the mass of 8.92 cm\(^3\) of limestone?

Answer :

Answer:

[tex]\boxed {\boxed {\sf 24.2624 \ g}}}[/tex]

Explanation:

Density measures mass per volume. The volume is

[tex]\rho=\frac{m}{v}[/tex]

The density of limestone is 2.72 grams per cubic centimeter. We have a piece of limestone with a volume of 8.92 cubic centimeters.

  • ρ= 2.72 g/cm³
  • v= 8.92 cm₃

Substitute the values into the formula.

[tex]2.72 \ g/cm^3=\frac{m}{8.92 \ cm^3}[/tex]

Now we solve for m, the mass, by isolating the variable.

m is being divided by 8.92 cubic centimeters. The inverse of division is multiplication, so we multiply both sides by 8.92 cubic centimeters.

[tex]8.92 \ cm^3 * 2.72 \ g/cm^3=\frac{m}{8.92 \ cm^3}* 8.92 \ cm^2[/tex]

[tex]8.92 \ cm^3 * 2.72 \ g/cm^3=m[/tex]

The units of cubic centimeters cancel out.

[tex]24.2624 \ g =m[/tex]

The mass of this piece of limestone is 24.2624 grams.

it should be 24.2624 because if there’s 2.72g in every cm3 and there are 8.92 cm3, then you simply multiply the two numbers
hope this helped :)