Answer :
To determine the heat capacity of the calorimeter, we can follow these steps:
1. Calculate the Moles of Aniline:
We are given the mass of aniline as 6.55 g and its molar mass as 93.13 g/mol. To find the moles of aniline, use the formula:
[tex]\[
\text{moles of aniline} = \frac{\text{mass}}{\text{molar mass}} = \frac{6.55 \, \text{g}}{93.13 \, \text{g/mol}}
\][/tex]
This calculation gives approximately 0.0703 moles of aniline.
2. Calculate the Heat Released:
The standard enthalpy change of the reaction [tex]\((\Delta H^{\circ}_{rxn})\)[/tex] is given as [tex]\(-1.28 \times 10^4 \, \text{kJ}\)[/tex] for the combustion of aniline according to the balanced equation. To find the heat released ([tex]\(q\)[/tex]) during the combustion of the given moles of aniline:
[tex]\[
q = \text{moles of aniline} \times \Delta H^{\circ}_{rxn} = 0.0703 \times (-1.28 \times 10^4 \, \text{kJ/mol})
\][/tex]
This results in approximately [tex]\(-900.25 \, \text{kJ}\)[/tex] of heat released.
3. Calculate the Heat Capacity of the Calorimeter:
The heat capacity of the calorimeter ([tex]\(C\)[/tex]) can be calculated using the formula:
[tex]\[
C = \frac{q}{\Delta T}
\][/tex]
where [tex]\(\Delta T\)[/tex] is the change in temperature, which is 32.9°C. Substituting the values:
[tex]\[
C = \frac{-900.25 \, \text{kJ}}{32.9 \, \text{°C}}
\][/tex]
This calculation gives approximately [tex]\(-27.36 \, \text{kJ/°C}\)[/tex].
This result indicates that the heat capacity of the calorimeter is about [tex]\(-27.36 \, \text{kJ/°C}\)[/tex]. However, since heat capacity is typically considered a positive value, we can consider the magnitude, which is closest to none of the given options. There might be an issue with the options that were provided.
1. Calculate the Moles of Aniline:
We are given the mass of aniline as 6.55 g and its molar mass as 93.13 g/mol. To find the moles of aniline, use the formula:
[tex]\[
\text{moles of aniline} = \frac{\text{mass}}{\text{molar mass}} = \frac{6.55 \, \text{g}}{93.13 \, \text{g/mol}}
\][/tex]
This calculation gives approximately 0.0703 moles of aniline.
2. Calculate the Heat Released:
The standard enthalpy change of the reaction [tex]\((\Delta H^{\circ}_{rxn})\)[/tex] is given as [tex]\(-1.28 \times 10^4 \, \text{kJ}\)[/tex] for the combustion of aniline according to the balanced equation. To find the heat released ([tex]\(q\)[/tex]) during the combustion of the given moles of aniline:
[tex]\[
q = \text{moles of aniline} \times \Delta H^{\circ}_{rxn} = 0.0703 \times (-1.28 \times 10^4 \, \text{kJ/mol})
\][/tex]
This results in approximately [tex]\(-900.25 \, \text{kJ}\)[/tex] of heat released.
3. Calculate the Heat Capacity of the Calorimeter:
The heat capacity of the calorimeter ([tex]\(C\)[/tex]) can be calculated using the formula:
[tex]\[
C = \frac{q}{\Delta T}
\][/tex]
where [tex]\(\Delta T\)[/tex] is the change in temperature, which is 32.9°C. Substituting the values:
[tex]\[
C = \frac{-900.25 \, \text{kJ}}{32.9 \, \text{°C}}
\][/tex]
This calculation gives approximately [tex]\(-27.36 \, \text{kJ/°C}\)[/tex].
This result indicates that the heat capacity of the calorimeter is about [tex]\(-27.36 \, \text{kJ/°C}\)[/tex]. However, since heat capacity is typically considered a positive value, we can consider the magnitude, which is closest to none of the given options. There might be an issue with the options that were provided.
