Answer :
Final answer:
To raise the temperature of a 5 kg piece of lead from 40°C to 58°C, the energy required is 11520 Joules, calculated using the formula Q = mcΔT.
Explanation:
The student is asking how much energy is required to raise the temperature of a 5 kg piece of lead from 40°C to 58°C. The specific heat capacity of lead is given as 128 J/kg·K. To find the energy required, we use the formula:
Q = mcΔT
where:
- Q is the heat in joules,
- m is the mass in kilograms,
- c is the specific heat capacity,
- ΔT is the change in temperature in Kelvin (which is the same as the change in Celsius).
First, calculate the change in temperature:
ΔT = 58°C - 40°C = 18°C
Then, plug in the values into the formula:
Q = (5 kg) × (128 J/kg·K) × (18 K)
Q = 5 × 128 × 18
Q = 11520 J
Therefore, the energy required to raise the temperature of the 5 kg piece of lead is 11520 Joules.
