High School

Lead has a specific heat capacity of 128 J/kg·K. How much energy is required to raise the temperature of a 5 kg piece of lead from 40°C to 58°C?

Answer :

Final answer:

To raise the temperature of a 5 kg piece of lead from 40°C to 58°C, the energy required is 11520 Joules, calculated using the formula Q = mcΔT.

Explanation:

The student is asking how much energy is required to raise the temperature of a 5 kg piece of lead from 40°C to 58°C. The specific heat capacity of lead is given as 128 J/kg·K. To find the energy required, we use the formula:

Q = mcΔT

where:

  • Q is the heat in joules,
  • m is the mass in kilograms,
  • c is the specific heat capacity,
  • ΔT is the change in temperature in Kelvin (which is the same as the change in Celsius).

First, calculate the change in temperature:

ΔT = 58°C - 40°C = 18°C

Then, plug in the values into the formula:

Q = (5 kg) × (128 J/kg·K) × (18 K)

Q = 5 × 128 × 18

Q = 11520 J

Therefore, the energy required to raise the temperature of the 5 kg piece of lead is 11520 Joules.