Select the correct answer from each drop-down menu.

1. If a heterozygous male with the genotype [tex]Ww[/tex] is mated with a homozygous recessive female of genotype [tex]ww[/tex], there is a chance that [tex]\square[/tex] of the offspring will be heterozygous.

[tex]
\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{array}
\]
[/tex]

2. If the heterozygous [tex]Ww[/tex] is crossed with a homozygous dominant [tex]WW[/tex], then the probability of having a homozygous recessive offspring is

[tex]
\[
\begin{array}{|c|c|c|}
\hline
& W & w \\
\hline
W & WW & Ww \\
\hline
w & WW & Ww \\
\hline
\end{array}
\]
[/tex]

Sure! Let's go through the problem step by step.

Part 1: Crossing a heterozygous male (Ww) with a homozygous recessive female (ww)

1. Identify the genotypes involved:
- The heterozygous male genotype is Ww.
- The homozygous recessive female genotype is ww.

2. Set up the Punnett square for this cross:

- The columns represent the alleles from the male: W and w.
- The rows represent the alleles from the female: w and w.

```
| | W | w |
|-----|-----|-----|
| w | Ww | ww |
| w | Ww | ww |
```

3. Determine the genotypes of the offspring:
- From the Punnett square, the possible genotypes are:
- Ww: appearing 2 times
- ww: appearing 2 times

4. Calculate the probability of heterozygous offspring (Ww):
- There are 2 heterozygous offspring (Ww) out of a total of 4 offspring.
- This results in a probability of 2 out of 4, which simplifies to 50%.

Part 2: Crossing a heterozygous (Ww) individual with a homozygous dominant (WW)

1. Identify the genotypes involved:
- The heterozygous genotype is Ww.
- The homozygous dominant genotype is WW.

2. Set up the Punnett square for this cross:

- The columns represent the alleles from the heterozygous individual: W and w.
- The rows represent the alleles from the homozygous dominant individual: W and W.

```
| | W | w |
|-----|-----|-----|
| W | WW | Ww |
| W | WW | Ww |
```

3. Determine the genotypes of the offspring:
- From the Punnett square, the possible genotypes are:
- WW: appearing 2 times
- Ww: appearing 2 times

4. Calculate the probability of homozygous recessive offspring (ww):
- There are no homozygous recessive offspring (ww).
- Therefore, the probability of having a homozygous recessive offspring is 0%.

So, the overall results are:
- There is a 50% chance of an offspring being heterozygous Ww when crossing Ww with ww.
- There is a 0% chance of an offspring being homozygous recessive ww when crossing Ww with WW.