College

A movie theater charges [tex]$11[/tex] for each full-price ticket and [tex]$8.25[/tex] for each reduced-price ticket. For one movie showing, the theater sold a total of 214 full-price and reduced-price tickets for [tex]\$2,145[/tex]. Which of the following systems of equations could be used to determine the number of full-price tickets, [tex]f[/tex], and the number of reduced-price tickets, [tex]r[/tex], sold?

A.
[tex] f + r = 214 [/tex]
[tex] 11f + 8.25r = 2,145 [/tex]

B.
[tex] f + r = 2,145 [/tex]
[tex] 8.25f + 11r = 214 [/tex]

C.
[tex] f + r = 2,145 [/tex]
[tex] 11f + 8.25r = 214 [/tex]

D.
[tex] f + r = 214 [/tex]
[tex] 8.25f + 11r = 2,145 [/tex]

Answer :

To solve the problem, we need to set up a system of equations based on the information provided about ticket sales at the movie theater.

1. Identify the Variables:
- Let [tex]\( f \)[/tex] be the number of full-price tickets sold.
- Let [tex]\( r \)[/tex] be the number of reduced-price tickets sold.

2. Translate the Information into Equations:
- We know the total number of tickets sold is 214. So, we can express this as:
[tex]\[
f + r = 214
\][/tex]
- The total revenue from selling these tickets is \[tex]$2,145. We also know the price per ticket:
- Full-price ticket: \$[/tex]11 each
- Reduced-price ticket: \$8.25 each
- The revenue equation using the ticket prices becomes:
[tex]\[
11f + 8.25r = 2145
\][/tex]

3. System of Equations:
With the two equations identified, we have the system:
- Equation 1: [tex]\( f + r = 214 \)[/tex]
- Equation 2: [tex]\( 11f + 8.25r = 2145 \)[/tex]

This system of equations will allow us to solve for the number of full-price tickets [tex]\( f \)[/tex] and reduced-price tickets [tex]\( r \)[/tex] sold.

The correct system of equations is:
- [tex]\( f + r = 214 \)[/tex]
- [tex]\( 11f + 8.25r = 2145 \)[/tex]

This setup will help find out how many of each type of ticket were sold to achieve the total revenue and the total ticket sales.