College

JF is a 62-year-old male admitted with diabetes and peripheral neuropathy.

**Medications:**
- Janumet XR 100/1000 daily
- Lyrica 50 mg TID
- Lisinopril 10 mg daily
- Norco 5/325 HS PRN
- D5NS + 20 mEq KCl

The hospital has 1-liter premixed bags of D5NS + 20 mEq KCl, and JF's fluid has been running at 80 mL/hr for 8 hours. How many mmols of KCl has the patient received?

(MW K = 39; MW Cl = 35.5).

(Answer must be numeric; no units or commas.)

Answer :

Final answer:

The patient received 12.8 mmols of KCl from the IV solution administered at a rate of 80 mL/hr for 8 hours, given the solution contains 20 mEq KCl per liter.

Explanation:

The solution is composed of D5NS + 20 mEq KCl per liter. To compute the amount of KCl received, we first calculate the total volume of solution given: 80 mL/hr * 8 hrs = 640 mL.

Given that there are 20 mEq of KCl per liter (1000 mL) of the solution, the patient received a total volume that's a fraction of a liter, so we apply a simple proportion to find the milliequivalents of KCl delivered:

(20 mEq KCl / 1000 mL) * 640 mL = 12.8 mEq KCl.

Since mEq directly translates to mmol for KCl (1 mEq KCl = 1 mmol KCl), the patient received 12.8 mmols of KCl.