If the sum of two consecutive numbers is 71 and one number is \( x \), then the other number is:

A. \( x + (x+1) = 71 \)
B. \( x + (x+2) = 71 \)
C. \( x + x = 71 \)
D. None of these

We are given that the sum of two consecutive numbers is 71. Let's call these numbers "x" and "x + 1". The reason we add 1 to "x" is because the numbers are consecutive, so the second number is one more than the first.

So, we have the equation:

x + (x + 1) = 71

Now, let's solve this equation step by step:

Combine the terms on the left side:

2x + 1 = 71

Subtract 1 from both sides:

2x = 70

Divide both sides by 2:

x = 35

Now we know that one of the numbers is 35 (x), and the other consecutive number is:

x + 1 = 35 + 1 = 36

So, the two consecutive numbers are 35 and 36, and indeed, their sum is 71.

Therefore, the correct option is:

b) x + (x + 1) = 71

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If the sum of two consecutive numbers is 71 and one number is \( x \), then the other number is:A. \( x + (x+1) = 71 \) B. \( x + (x+2) = 71 \) C. \( x + x = 71 \) D. None of these

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Other Questions

If the sum of two consecutive numbers is 71 and one number is \( x \), then the other number is:

A. \( x + (x+1) = 71 \)
B. \( x + (x+2) = 71 \)
C. \( x + x = 71 \)
D. None of these