Answer :
Final answer:
In the given x86 assembly code, the final value of the ax register after executing the loop will be 12.
Explanation:
In this x86 assembly language code, we have two instructions: mov ax,7 which assigns the value 7 to the ax register, and mov ecx,5, which assigns the value 5 to the ecx register. Then we enter a loop labeled l1: which increments ax by 1 (inc ax) and then decrements ecx by 1 (loop l1), continuing the loop until ecx reaches 0.
The loop runs 5 times (the initial value of ecx), during which the ax register increments from its initial value of 7. Therefore, after the loop completes, the final value of ax will be 7 plus 5, or 12.
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