The concentration of [tex]$Mg^{2+}$[/tex] ions in seawater is about 1.290 g/kg. If the density of seawater is 1.04 g/mL, determine its molarity.

a. 1.24 M
b. 1.31 M
c. 1.42 M
d. 1.55 M

Answer :

Final answer:

To find the molarity of Mg2+ ions in seawater, we convert the given mass concentration to moles using the molar mass, and then divide by the volume in liters. None of the above answer is correct.

Explanation:

The question involves the calculation of the molarity of Mg2+ ions in seawater from a given density and concentration in g/kg. Seawater has a density of 1.026 g/cm3 and contains 1272 parts per million of magnesium as Mg2+ (aq) by mass.

To solve this, first we convert the density of seawater from g/cm3 to g/L (since 1 cm3 is equivalent to 1 mL). Next, we use the mass concentration of magnesium to find the mass of magnesium in a liter of seawater.

Then we can convert this mass to moles using the molar mass of Mg2+, which is approximately 24.305 g/mol. Finally, to find the molarity, we divide the number of moles by the volume of the solution in liters.

None of the above answer is correct.