Answer :
Final answer:
The atom density of NO3 in uranyl nitrate can be calculated by finding the number of moles of U-235 and using the molarity of uranyl nitrate. The atom density of NO3 is 9.92 M/L.
Explanation:
The atom density of NO3 in uranyl nitrate can be calculated by first finding the number of moles of U-235 in 2.1 kg, and then using the molarity of uranyl nitrate to determine the number of moles of NO3. The atom density of NO3 is then obtained by dividing the number of moles by the volume of uranyl nitrate.
To find the number of moles of U-235, we divide the mass by the molar mass of U-235. The molar mass of U-235 is 235 g/mol. So, 2.1 kg (or 2100 g) of U-235 is equal to 2100 g / 235 g/mol = 8.94 mol.
Next, we can calculate the number of moles of NO3 using the molarity of uranyl nitrate. Molarity is defined as moles of solute per liter of solution. The molarity can be calculated using the formula M = (mass %/atomic mass) * (1000/volume). The atomic mass of NO3 is 62 g/mol. We have a weight enrichment of 93%, so the mass of NO3 is 0.93 * 2100 g = 1953 g. The volume of uranyl nitrate is given as 56000 cc, which is equal to 56000 mL or 56 L. Plugging in these values into the molarity formula gives M = (1953 g / 62 g/mol) * (1000 mL/56 L) = 555.32 M.
Finally, the atom density of NO3 is calculated by dividing the number of moles of NO3 by the volume of uranyl nitrate. The volume of uranyl nitrate is given as 56000 cc or 56 L. So, the atom density of NO3 is 555.32 M / 56 L = 9.92 M/L.
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