High School

A 7.0 kg ball is launched at 54 m/s at an angle of 67 degrees.

What is the initial kinetic energy of the ball?

Answer :

Therefore, the initial kinetic energy of the ball is approximately 10,587 J.

The initial kinetic energy of a 7.0 kg ball launched at 54 m/s at an angle of 67 degrees can be calculated as follows:

Step 1: Find the horizontal and vertical components of the velocity:

vx = v cos θ

vx = 54 cos 67°

vx = 21.9 m/s

vy = v sin θ

vy = 54 sin 67°

vy = 50.6 m/s

Step 2: Find the magnitude of the velocity:

|v| = √(vx² + vy²)

|v|= √(21.9² + 50.6²)

|v| = 55.4 m/s

Step 3: Calculate the initial kinetic energy of the ball:

KE = (1/2)mv²

KE = (1/2)(7.0 kg)(55.4 m/s)²

KE ≈ 10,587 J

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