Answer :
Final answer:
If a walnut comb chicken was crossed to a single comb chicken and in the F1 half were walnut and half were pea comb the genotype of the walnut comb parent was Ww, hence correct answer is b - Ww.
Explanation:
In chickens, walnut comb (W) is dominant over single comb(w), and pea comb (P) is dominant over single comb. Therefore, the walnut comb chicken must be heterozygous for the walnut comb gene, represented as Ww. When crossed with a single comb chicken (ww), all the F1 offspring will inherit one allele from each parent.
Half of the F1 offspring will inherit the dominant walnut comb allele (W) from the walnut comb parent, resulting in a walnut comb phenotype, while the other half will inherit the recessive single comb allele (w) from the single comb parent, resulting in a pea comb phenotype.
