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------------------------------------------------ I began this reaction with 25.5 grams of lithium hydroxide and 35.8 grams of potassium chloride (KCl). What is my theoretical yield of lithium chloride?

To calculate the theoretical yield of lithium chloride, we need to determine the limiting reagent between lithium hydroxide and KCl.

First, we can write the balanced chemical equation for the reaction between lithium hydroxide and KCl:

LiOH + KCl -> LiCl + KOH

Next, we can calculate the number of moles of each reactant:

moles of LiOH = 25.5 g / 23.95 g/mol = 1.065 mol
moles of KCl = 35.8 g / 74.55 g/mol = 0.480 mol

Since KCl has fewer moles than LiOH, it is the limiting reagent. This means that all of the KCl will be used up in the reaction, and any excess LiOH will be left over.

To calculate the theoretical yield of LiCl, we can use the number of moles of KCl as the starting point:

moles of LiCl = moles of KCl = 0.480 mol

Finally, we can convert the number of moles of LiCl to grams:

mass of LiCl = moles of LiCl x molar mass of LiCl
mass of LiCl = 0.480 mol x 42.39 g/mol
mass of LiCl = 20.3 g

Therefore, the theoretical yield of LiCl is 20.3 grams.