Answer :
The pressure applied to the ground by a 112 kg man standing on square stilts measuring 0.06 m on each edge is 152,622.22 Pa.
To calculate the pressure applied to the ground by the man standing on square stilts, we first need to know the total force he exerts on the ground due to gravity, which is his weight. This can be found by multiplying his mass by the acceleration due to gravity. The pressure is then calculated by dividing the force by the area over which it is applied.
The mass of the man is 112 kg, and the acceleration due to gravity is 9.81 m/s2. Therefore, his weight, or the force exerted on the ground, is F = m imes g = 112 kg imes 9.81 m/s2 = 1098.72 N (newtons).
The area of one stilt is given by the square of the edge length since it is a square. The edge length is 0.06 m, so the area A = 0.06 m imes 0.06 m = 0.0036 m2. Since he stands on two stilts, the total area is twice that: 0.0072 m2.
The pressure P exerted on the ground is the force divided by the total area over which the force is distributed:
P = F / A = 1098.72 N / 0.0072 m2 = 152,622.22 Pa (pascals).
