Two identical violin strings, stretched with the same tension (600N), have a fundamental frequency of 440.0 Hz. One of the strings is tuned by matching the tension. Once this is done, what is the frequency of the other string?

Two identical violin strings at the same tension will vibrate at the same frequency. Thus, even after tuning, so long as the tension is matched, the other string will vibrate at 440.0 Hz.

Explanation:

The question is addressing the concept of resonant frequencies in Physics, specifically with regards to identical violin strings. When two identical violin strings are stretched with the same tension, as per the question scenario, they vibrate at the same initial frequency— in this case, 440.0 Hz.

A crucial takeaway here is that the frequency of a string is determined by the tension of the string and its length, among other factors

Given that the tension is matched between the two strings, and we know that the strings are identical (so we assume their length is the same), the frequency of the other string after tuning will also be 440.0 Hz. This is because the frequency is a property of the physical makeup of the string and the tension applied to it. When these conditions are identical, then the resulting frequency of vibrations will also be identical.

Learn more about Resonant Frequencies here:

https://brainly.com/question/32615151

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