High School

How much ice (in grams) would have to melt to absorb 231 kJ of energy? The enthalpy of fusion for ice at 0 ∘C is 6.02 kJ/mol.

A. 38.4 grams
B. 76.8 grams
C. 153.6 grams
D. 307.2 grams

Answer :

To determine how much ice would have to melt to absorb 231 kJ of energy, we can use the enthalpy of fusion for ice and set up a proportion. The correct answer is Option A: 38.4 grams.

To determine how much ice would have to melt to absorb 231 kJ of energy, we need to use the enthalpy of fusion for ice. The enthalpy of fusion tells us how much energy is required to convert 1 mole of ice to water at 0 ∘C. The enthalpy of fusion for ice is 6.02 kJ/mol.

We can use this information to set up a proportion:
231 kJ = x grams
6.02 kJ/mol

By cross-multiplying and solving for x, we find:

x = (231 kJ * 1 mol) / (6.02 kJ)

x = 38.404 grams

Therefore, the correct answer is Option A: 38.4 grams.

Learn more about enthalpy of fusion here:

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