Answer :
Final answer:
The force necessary to accelerate a 55 kg biker and his 20 kg bike at 3 m/s² is 225 Newtons, calculated using Newton's second law of motion.
Explanation:
The subject of this question is Physics, specifically focusing on the concept of force and acceleration according to Newton's second law (F=ma). The problem asks how much force is necessary to accelerate a 55 kg biker and his 20 kg bike at 3 m/s². Using Newton's second law, we need to multiply the total mass by the acceleration. The total mass of the biker and the bike is 75 kg (55 kg + 20 kg). Thus, the force (F) can be calculated as F = ma = 75 kg * 3 m/s² = 225 N. Therefore, the answer is 225 N.
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Final answer:
The force necessary to accelerate a 55kg biker and his 20kg bike at 3m/s² is d) 225 Newtons. This is computed by using Newton's second law of motion, F=ma, where F is force, m is the total mass (75kg), and a is acceleration.
Explanation:
This problem is a classic application of Newton's second law, which can be formulated as F = ma, meaning that force equals mass times acceleration. In this case, the total mass being accelerated is the mass of the biker and his bike combined, which is 55kg (biker) + 20kg (bike) = 75kg. The given acceleration is 3m/s².
Now, we use the formula F = ma: F = 75kg * 3m/s² = 225N.
Therefore, the necessary force to accelerate the biker and his bike at this rate is 225N.
So, the answer is (d) 225N; the force necessary to accelerate both the biker (55kg) and his bike (20kg) at 3m/s² is indeed 225 Newtons.
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