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------------------------------------------------ How many moles of zinc (Zn) are in [tex]1.57 \times 10^{24}[/tex] Zn atoms?

Answer :

Final answer:

The number of moles of zinc in 1.57 x 10^24 Zn atoms is approximately 2.61 moles. This calculation is achieved by dividing the number of atoms by Avogadro's number.

Explanation:

To find the number of moles of a substance, you can use Avogadro's number, which is 6.022 x 10^23 atoms per one mole. You need to divide the number of atoms, which is 1.57 x 10^24, by Avogadro's number.

The calculation looks like this: (1.57 x 10^24) / (6.022 x 10^23) = 2.61 moles, approximately.

So, there are approximately 2.61 moles of zinc in 1.57 x 10^24 Zn atoms.

Learn more about Zinc Moles here:

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Using Avogadro's number (6.022 x 10²³ atoms in a mole), we find there are 2.61 moles of zinc in 1.57x10²⁴ zinc atoms.

To calculate the quantity in moles of a given number of atoms, we use Avogadro's number, which states there are 6.022 x 10²³ atoms in a mole. Therefore, to find the number of moles of zinc in 1.57x10²⁴ atoms, we would divide the total number of atoms by Avogadro's number. The calculation as follows:

1.57 x 10²⁴ atoms / 6.022 x 10²³ atoms/mol = 2.61 mol

The main answer is 2.61 moles of zinc.

In conclusion, that there are 2.61 moles of zinc in 1.57x10²⁴ zinc atoms when we apply Avogadro's number.

Learn more about Avogadro's number here:

https://brainly.com/question/33720401

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