Answer :

Moles of MgS2O3 = 197/molar mass of MgS2O3
= 197/136.42
= 1.44 MOLES.

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Final answer:

To find the number of moles of MgS2O3 in 197 grams, divide the mass by the molar mass of MgS2O3.

Explanation:

To find the number of moles of MgS2O3 in 197 grams, we need to use the molar mass of MgS2O3 which is 176.124 g/mol. We can calculate the number of moles by dividing the mass by the molar mass.

Number of moles = Mass / Molar Mass

Number of moles = 197 g / 176.124 g/mol = 1.1178 moles

Therefore, there are approximately 1.1178 moles of MgS2O3 in 197 grams.

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