How many moles are in 98.3 grams of aluminum hydroxide, [tex]$Al(OH)_3$[/tex]?

Sure, let's go through the steps to find out how many moles are in 98.3 grams of aluminum hydroxide, [tex]$ \text{Al(OH)}_3 $[/tex].

1. Identify the Elements and Their Atomic Masses:
- Aluminum (Al) has an atomic mass of approximately 26.98 g/mol.
- Oxygen (O) has an atomic mass of approximately 16.00 g/mol.
- Hydrogen (H) has an atomic mass of approximately 1.008 g/mol.

2. Calculate the Molar Mass of [tex]$ \text{Al(OH)}_3 $[/tex]:
[tex]$ \text{Al(OH)}_3 $[/tex] consists of one aluminum atom, three oxygen atoms, and three hydrogen atoms.
- The total molar mass of aluminum hydroxide is calculated as follows:
- Molar mass of Al [tex]$ = 26.98 $[/tex] g/mol
- Molar mass of O in 3 OH groups [tex]$ = 3 \times 16.00 = 48.00 $[/tex] g/mol
- Molar mass of H in 3 OH groups [tex]$ = 3 \times 1.008 = 3.024 $[/tex] g/mol

The total molar mass of [tex]$ \text{Al(OH)}_3 = 26.98 + 48.00 + 3.024 = 78.004 $[/tex] g/mol.

3. Calculate the Number of Moles:
To find out how many moles are in 98.3 grams of aluminum hydroxide, use the formula:

[tex]\[
\text{moles} = \frac{\text{mass}}{\text{molar mass}} = \frac{98.3 \, \text{g}}{78.004 \, \text{g/mol}}
\][/tex]

This calculation results in approximately 1.2602 moles.

Therefore, there are approximately 1.26 moles of aluminum hydroxide in 98.3 grams.