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If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a chance that [tex]$\square$[/tex] of the offspring will be heterozygous.

\[
\begin{tabular}{|c|c|c|}
\hline
& W & w \\
\hline
w & Ww & ww \\
\hline
w & Ww & ww \\
\hline
\end{tabular}
\]

If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous recessive offspring is [tex]$\square$[/tex].

\[
\begin{tabular}{|c|c|c|}
\hline
& W & w \\
\hline
W & WW & Ww \\
\hline
W & WW & WW \\
\hline
\end{tabular}
\]

Sure! Let's go through the problem step-by-step:

### First Part: Mating a Heterozygous Male (Ww) with a Homozygous Recessive Female (ww)

1. Identify the Parent Genotypes:
- Male: Ww (heterozygous)
- Female: ww (homozygous recessive)

2. Set Up the Punnett Square:
```
| | W | w |
|---|---|---|
| w | Ww| ww|
| w | Ww| ww|
```

3. Fill The Punnett Square:
- The male can pass either W or w.
- The female can only pass w.

Therefore:
- If the male passes W, the offspring genotype will be Ww (heterozygous).
- If the male passes w, the offspring genotype will be ww (homozygous recessive).

4. Determine the Genotype Probabilities:
- Ww (heterozygous): 2 out of 4 times (or 1/2 of the time)
- ww (homozygous recessive): 2 out of 4 times (or 1/2 of the time)

5. Answer the Question:
- There is a 0.5 (or 50%) chance that their offspring will be heterozygous (Ww).

### Second Part: Crossing Heterozygous (Ww) with Homozygous Dominant (WW)

1. Identify the Parent Genotypes:
- Heterozygous: Ww
- Homozygous Dominant: WW

2. Set Up the Punnett Square:
```
| | W | W |
|---|---|---|
| W | WW| WW|
| w | Ww| Ww|
```

3. Fill The Punnett Square:
- One parent always contributes W (since the homozygous dominant parent can only pass W).
- The other parent (heterozygous Ww) can pass either W or w.

Therefore:
- If the heterozygous parent passes W, the offspring genotype will be WW (homozygous dominant).
- If the heterozygous parent passes w, the offspring genotype will be Ww (heterozygous).

4. Determine the Genotype Probabilities:
- WW (homozygous dominant): 2 out of 4 times (or 1/2 of the time)
- Ww (heterozygous): 2 out of 4 times (or 1/2 of the time)
- ww (homozygous recessive): 0 out of 4 times (not possible)

5. Answer the Question:
- There is a 0.0 chance (or 0%) that their offspring will be homozygous recessive (ww).

### Summary:
1. If a heterozygous male (Ww) is mated with a homozygous recessive female (ww), there is a 0.5 chance (or 50%) that the offspring will be heterozygous (Ww).
2. If a heterozygous (Ww) is crossed with a homozygous dominant (WW), the probability of having a homozygous recessive offspring (ww) is 0.0 (or 0%).

I hope this helps you understand the problem better! If you have any more questions, feel free to ask.