Answer :
The amount of kilocalories generated when the brakes are used to bring a 1200-kg car to rest from a speed of 93 km/h is approximately 1796.7 kcal.
To calculate the amount of kilocalories generated, we need to first calculate the kinetic energy of the car using the formula:
⇒ KE = (1/2)mv^2
where m is the mass of the car in kg, and v is the velocity of the car in m/s.
Converting the speed of the car from km/h to m/s, we get:
⇒ v = (93 km/h) × (1000 m/km) / (3600 s/h)
⇒ = 25.83 m/s
Plugging in the values, we get:
⇒ KE = (1/2) × (1200 kg) × (25.83 m/s)^2
⇒ = 472,355.04 J
Next, we need to convert the kinetic energy into kilocalories (kcal) using the conversion factor:
⇒ 1 kcal = 4184 J
Dividing the kinetic energy by the conversion factor, we get
⇒ KE in kcal = 472,355.04 J / 4184 J/kcal
⇒ = 1796.7 kcal
Therefore, the amount of kilocalories generated when the brakes are used to bring the car to rest is approximately 1796.7 kcal.
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