Answer :
To arrange the polynomial [tex]\(4x^2 - x + 8x^6 + 3 + 2x^{10}\)[/tex] in descending order, you need to organize the terms based on the degree of [tex]\(x\)[/tex], starting from the highest to the lowest.
Here’s how to do it step-by-step:
1. Identify the Degrees of Each Term:
- [tex]\(4x^2\)[/tex] has a degree of 2.
- [tex]\(-x\)[/tex] has a degree of 1.
- [tex]\(8x^6\)[/tex] has a degree of 6.
- [tex]\(3\)[/tex] (the constant term) effectively has a degree of 0.
- [tex]\(2x^{10}\)[/tex] has a degree of 10.
2. Arrange the Terms in Descending Order of Degree:
- Start with the term that has the highest degree: [tex]\(2x^{10}\)[/tex].
- Next is the degree 6 term: [tex]\(8x^6\)[/tex].
- Then, the degree 2 term: [tex]\(4x^2\)[/tex].
- Followed by the degree 1 term: [tex]\(-x\)[/tex].
- Finally, the constant term: [tex]\(3\)[/tex].
3. Write the Polynomial in Order:
- Combine all these terms while keeping their original coefficients and signs.
The polynomial arranged in descending order is:
[tex]\[ 2x^{10} + 8x^6 + 4x^2 - x + 3 \][/tex]
Therefore, the correct option is:
A. [tex]\(2x^{10} + 8x^6 + 4x^2 - x + 3\)[/tex]
Here’s how to do it step-by-step:
1. Identify the Degrees of Each Term:
- [tex]\(4x^2\)[/tex] has a degree of 2.
- [tex]\(-x\)[/tex] has a degree of 1.
- [tex]\(8x^6\)[/tex] has a degree of 6.
- [tex]\(3\)[/tex] (the constant term) effectively has a degree of 0.
- [tex]\(2x^{10}\)[/tex] has a degree of 10.
2. Arrange the Terms in Descending Order of Degree:
- Start with the term that has the highest degree: [tex]\(2x^{10}\)[/tex].
- Next is the degree 6 term: [tex]\(8x^6\)[/tex].
- Then, the degree 2 term: [tex]\(4x^2\)[/tex].
- Followed by the degree 1 term: [tex]\(-x\)[/tex].
- Finally, the constant term: [tex]\(3\)[/tex].
3. Write the Polynomial in Order:
- Combine all these terms while keeping their original coefficients and signs.
The polynomial arranged in descending order is:
[tex]\[ 2x^{10} + 8x^6 + 4x^2 - x + 3 \][/tex]
Therefore, the correct option is:
A. [tex]\(2x^{10} + 8x^6 + 4x^2 - x + 3\)[/tex]