Answer :
17.42 grams of water (H₂O) will be produced when 35.8 grams of calcium hydroxide (Ca(OH)₂) reacts with hydrochloric acid.
Given,
Mass of calcium hydroxide (Ca(OH)₂) = 35.8 grams
Molar mass of calcium hydroxide (Ca(OH)₂) = 74.10 g/mol
Molar mass of water (H₂O) = 18.02 g/mol
The balanced equation for the reaction between calcium hydroxide and hydrochloric acid is: Ca(OH)₂ + 2HCl → CaCl₂ + 2H₂O
For every 1 mole of calcium hydroxide that reacts, 2 moles of water are produced.
Moles = Mass / Molar mass
Moles of Ca(OH)₂ = 35.8/ 74.10 ≈ 0.483 mol
Moles of H₂O = 2 × Moles of Ca(OH)₂ = 2 × 0.483 = 0.966 mol
Mass = Moles × Molar mass
Mass of H₂O = 0.966 × 18.02 ≈ 17.42
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