Answer :
246.0 grams of ethanol, c2h5oh, can be boiled with 206.2 kj of heat energy? the molar heat of vaporization of ethanol is 38.6 kj/mol.
We can use the following equation to determine how much ethanol can be boiled using 206.2 kJ of heat energy:
q = n*ΔHvap
where n is the substance's (in moles) vaporized amount of ethanol, Hvap is the molar heat of vaporization of ethanol, and q is the amount of heat energy given.
First, we may use the equation to determine how much ethanol was vaporized:
q/ΔHvap = n
Inputting the values provided yields:
5.34 mol is equal to n = 206.2 kJ/38.6 kJ/mol.
Next, we can convert the amount of substance to mass using the molar mass of ethanol (46.07 g/mol):
m = n * M
where M is ethanol's molar mass.
When we change the values, we obtain:
246.0 g= 5.34 mol * 46.07 g/mol
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