Answer :
The bearing capacity of the foundation is greater than the column load, so the foundation is safe. The bearing capacity of the foundation is 27,600 psf.
The bearing capacity of a foundation can be determined using the Schmertmann's analysis. The Schmertmann's analysis is a method for calculating the bearing capacity of shallow foundations in sand.
The bearing capacity of a foundation is the maximum load that the foundation can support without failing.
The Schmertmann's analysis uses the following equation to calculate the bearing capacity of a foundation:
q = c + 0.5 * yz * Nq
where:
q is the bearing capacity (psf)
c is the cohesion of the soil (psf)
y is the moist unit weight of the soil (pcf)
z is the depth of the foundation (ft)
Nq is the bearing capacity factor
In your problem, the following values are given:
Column load = 190,000 lbs
Footing area = 10 ft x 10 ft = 100 ft^2
Footing depth = 3 ft
Moist unit weight of the soil = 124 pcf
Groundwater depth = 15 ft
N60 values of the sand = 50
The cohesion of the soil is assumed to be zero.
The bearing capacity factor, Nq, can be calculated using the following equation:
Nq = 15N60
Substituting the given values into the equations, we get:
q = 0 + 0.5 * 124 * 3 * 150 = 27,600 psf
Therefore, the bearing capacity of the foundation is 27,600 psf.
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The following question may be like this:
foundation design (use schmertmanns Analysis)
A 190,000 lbs column load is supported by a 10 ft square footing that is 3 ft deep. The bearing soil is a sand with y moist = 124 pcf. The groundwater is 15 feet deep. The N 60 values of the sand are: 0-6 ft deep N60 =13 6-10 ft deep N60=22 10-18 ft deep N60-29 18-21 ft deep N60-26 21-24 At deep N60-48 The sand's modulus (Es) = 7 N60 (in tsf). Compute the bearing capacity of the foundation.
