Dear beloved readers, welcome to our website! We hope your visit here brings you valuable insights and meaningful inspiration. Thank you for taking the time to stop by and explore the content we've prepared for you.
------------------------------------------------ For a certain commercial jet to achieve liftoff, its total weight cannot exceed 333,390 kg. Given the following information:

- The empty weight of the jet (i.e., no fuel or passengers) is 163,293 kg.
- There are 300 passengers aboard, each with an average weight of 75.0 kg.

Determine how many liters of jet fuel the jet can hold and still be able to take off from sea level with an outside temperature of 277 K. The specific gravity of jet fuel is 0.804.

We have, empty weight=163,293 kg

weight of 300 passengers=300x75=22500 kg

outside temp=277 k=4°C

Density of water at 4°C =p^ w=1000kg/m^ 3

here ,specific gravity of jet fuel S=0.804

S=p^ fuel/p^ water=0.804 (P= Passenger F= fuel)

P^ F=0.804x1000

=804kg/m^ 3

Max. possible weight of fuel=333,390-163,293-22,500.

=147597 kg.

weight of fuel=density x volume=147597

volume=147597/804

=183.578 m^ 3

We Know, m^ 3=264.172 gallons.

183.578 m^ 3=48496.16742 gallons.

So, Jet can hold 48496.16742 gallons of fuel.

To learn more about gravity of jet fuel
https://brainly.com/question/15058093
#SPJ4