Answer :
Final answer:
The total force on the side of the rectangular water trough is calculated by considering the depth to which the trough is filled with water along with the area of the side. The calculated force is approximately 45,031.25 N.
Explanation:
The total force exerted by a liquid on a surface is given by the equation P = ρghA, where P is pressure, ρ is the density of the liquid (in this case water, so it's 1000 kg/m³), g is the gravitational constant (9.8 m/s²), h is the height of the liquid, and A is the area of the surface.
Here, the area of the side of the rectangular water trough (A) is
1.25 m x 2.95 m = 3.6875 m².
The depth of the water (h) is 1.25 m, so put these values in the equation, we find:
P = 1000 kg/m³ x 9.8 m/s² x 1.25 m x 3.6875 m²
This gives us a total force of: 45,031.25 N.
Learn more about Pressure here: brainly.com/question/31544967
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