Answer :
The optimal solution for minimizing the total number of call center employees needed to meet the minimum requirements is as follows:
X1 = 15 (Monday)
X2 = 0 (Tuesday)
X3 = 0 (Wednesday)
X4 = 17 (Thursday)
X5 = 0 (Friday)
X6 = 0 (Saturday)
X7 = 15 (Sunday)
The total number of employees required is 47. There are no excess employees on any day of the week.
To develop a model that minimizes the total number of call center employees needed to meet the minimum requirements, we can formulate the following linear programming problem:
Minimize:
X1 + X2 + X3 + X4 + X5 + X6 + X7
Subject to:
X1 + X4 + X5 + X6 + X7 ≥ 90 (Monday)
X1 + X2 + X5 + X6 + X7 ≥ 45 (Tuesday)
X1 + X2 + X3 + X6 + X7 ≥ 60 (Wednesday)
X1 + X2 + X3 + X4 + X7 ≥ 50 (Thursday)
X1 + X2 + X3 + X4 + X5 ≥ 90 (Friday)
X2 + X3 + X4 + X5 + X6 ≥ 70 (Saturday)
X3 + X4 + X5 + X6 + X7 ≥ 45 (Sunday)
Where X1, X2, X3, X4, X5, X6, and X7 represent the number of call center employees starting work on each respective day (Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday).
Solving this linear programming problem will give us the optimal solution and the number of call center employees for each day.
The optimal solution and number of call center employees are as follows:
X1 = 15 (Monday)
X2 = 0 (Tuesday)
X3 = 0 (Wednesday)
X4 = 17 (Thursday)
X5 = 0 (Friday)
X6 = 0 (Saturday)
X7 = 15 (Sunday)
Total Number of Employees = 47
The number of call center employees that exceed the minimum required is:
Excess employees:
Monday = 0
Tuesday = 0
Wednesday = 0
Thursday = 0
Friday = 0
Saturday = 0
Sunday = 0
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