Middle School

A car purchased for $20,000 depreciates annually at a rate of 8%. The value of the car \( t \) years after its purchase is given by the expression \( 20000(0.92)^t \).

Which expression represents the monthly depreciated value at the rate at which the car is depreciating?

A. \( 20000(0.92)^{1/12} \)

B. \( 20000(0.92^2) \)

C. \( 20000(0.92)^{1} \)

D. \( 20000(0.92)^{12/120} \)

Answer :

The expression that represents the monthly depreciated value at the rate at which the car is depreciating is [tex]20000(0.92)^{\frac t{12}}[/tex]

The expression that represents the yearly depreciation of the value of the car is given as:

[tex]20000(0.92)^t[/tex]

There are 12 months in a year.

So, we divide the exponent t by 12 to calculate the monthly depreciation.

So, we have:

[tex]20000(0.92)^{\frac t{12}}[/tex]

Hence, the expression that represents the monthly depreciated value at the rate at which the car is depreciating is [tex]20000(0.92)^{\frac t{12}}[/tex]

Read more about exponential functions at:

https://brainly.com/question/11464095

Answer:O 20,000(0.9212) 120

Step-by-step explanation:

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