Answer :
Final answer:
The depth of the cubical aerated grit chamber necessary to treat a flow of 6.2 MGD with a design hydraulic retention time of 3 minutes is approximately 140.9 ft.
Explanation:
To determine the depth of a cubical aerated grit chamber, we need to use the given flow rate and design hydraulic retention time. First, let's convert the flow rate from MGD to ft3/min:
1 MGD = 1,000,000 gallons/day = 1,000,000/7.48 ft3/day = 133,689.84 ft3/day
6.2 MGD = 6.2 * 133,689.84 ft3/day = 828,932.7288 ft3/day
Next, we need to calculate the volume of the chamber:
Volume = Flow rate * Retention time
Volume = 828,932.7288 ft3/day * 3 min = 2,486,798.1864 ft3
Since the chamber is cubical, all sides have the same length. Let's assume the side length of the chamber is 'x' ft. The volume of a cube is given by:
Volume = x3
Equating the two volume equations, we have:
x3 = 2,486,798.1864 ft3
Taking the cube root of both sides, we find:
x = 140.9 ft
Therefore, the depth of the cubical aerated grit chamber necessary to treat a flow of 6.2 MGD with a design hydraulic retention time of 3 minutes is approximately 140.9 ft.
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