Answer :
Without the correct molar mass for C3H3, we cannot determine how many grams of water vapor will be produced. The molar masses provided in the brief don't match the given reactant, C3H3.
To determine how many grams of water vapor can be produced when starting with 37.1 grams of C3H3 and O2, we first need to ensure we have a balanced chemical equation:
C3H3 + 5O2 ightarrow 3CO2 + 4H2O
This tells us that 1 mole of C3H3 reacts with 5 moles of O2 to produce 3 moles of CO2 and 4 moles of H2O. Now, we need to find the molar mass of C3H3 which is (3x12.01 g/mol for carbon + 3x1.008 g/mol for hydrogen) and the molar mass of O2 which is (32 g/mol).
Since we do not have the molar mass for C3H3 given, we cannot proceed further with calculations. Therefore, we need to correct the formula for C3H3 and obtain the proper molar mass before we can answer the student's question.
