Answer :
We start by letting:
- \( A = 3865 \) as Bo's represented score. However, his actual score is obtained by placing the decimal point two places from the right. Thus, Bo’s actual score is
\[
\text{Bo's score} = \frac{3865}{100} = 38.65.
\]
- \( B = 29 \) represents the score of the player who scored 29 points. This means Mike’s score is 29.
- \( C = 100.2 \) is the total combined score of the three players.
Now, we first find the sum of Bo’s (actual) score and Mike’s score:
\[
38.65 + 29 = 67.65.
\]
To determine Cat’s score, we subtract the sum of Bo’s and Mike’s scores from the total score:
\[
\text{Cat's score} = C - (\text{Bo's score} + \text{Mike's score}) = 100.2 - 67.65 = 32.55.
\]
Thus, the answers to the problem are:
1. The value of \( A \) (Bo's represented score) is \(\boxed{3865}\).
2. The player who scored \( B \) (29 points) is \(\boxed{\text{Mike}}\).
3. The combined score \( C \) of the three players is \(\boxed{100.2}\).
4. The number of points that Cat scored is \(\boxed{32.55}\).
- \( A = 3865 \) as Bo's represented score. However, his actual score is obtained by placing the decimal point two places from the right. Thus, Bo’s actual score is
\[
\text{Bo's score} = \frac{3865}{100} = 38.65.
\]
- \( B = 29 \) represents the score of the player who scored 29 points. This means Mike’s score is 29.
- \( C = 100.2 \) is the total combined score of the three players.
Now, we first find the sum of Bo’s (actual) score and Mike’s score:
\[
38.65 + 29 = 67.65.
\]
To determine Cat’s score, we subtract the sum of Bo’s and Mike’s scores from the total score:
\[
\text{Cat's score} = C - (\text{Bo's score} + \text{Mike's score}) = 100.2 - 67.65 = 32.55.
\]
Thus, the answers to the problem are:
1. The value of \( A \) (Bo's represented score) is \(\boxed{3865}\).
2. The player who scored \( B \) (29 points) is \(\boxed{\text{Mike}}\).
3. The combined score \( C \) of the three players is \(\boxed{100.2}\).
4. The number of points that Cat scored is \(\boxed{32.55}\).
