High School

Based on the thermodynamic properties provided for water, determine the energy change when the temperature of 0.550 kg of water decreases from 103 °C to 33.0 °C.

____ kJ

Answer :

Final answer:

The energy change when the temperature of 0.550 kg of water decreased from 103 °C to 33.0 °C is -13.3 kJ.

Explanation:

To determine the energy change when the temperature of 0.550 kg of water decreased from 103 °C to 33.0 °C, we can use the equation:

Q = mcΔT

Where Q is the energy change, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature.

Given:

  • Mass of water (m) = 0.550 kg
  • Initial temperature (T1) = 103 °C
  • Final temperature (T2) = 33.0 °C
  • Specific heat capacity of water (c) = 4.184 J/g °C

First, convert the mass of water to grams:

0.550 kg × 1000 g/kg = 550 g

Next, calculate the change in temperature:

ΔT = T2 - T1 = 33.0 °C - 103 °C = -70.0 °C

Finally, plug in the values into the equation:

Q = (550 g)(4.184 J/g °C)(-70.0 °C) = -1.33 × 10^4 J

Since the question asks for the energy change in kJ, we can convert the answer:

-1.33 × 10^4 J = -13.3 kJ

Therefore, the energy change when the temperature of 0.550 kg of water decreased from 103 °C to 33.0 °C is -13.3 kJ.

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