Answer :
Final answer:
Both the hydrogen atom and the helium ion in the second excited state would have an angular momentum quantum number l of 2, making the option (d) l1 = 2, l2 = 2 correct.
Explanation:
The question pertains to the angular momentum of a hydrogen atom and a helium ion when they are in the second excited state. The angular momentum quantum number, denoted as l, can be determined by the principal quantum number n. For a hydrogen atom in the second excited state, n equals 3, which gives potential values of l as 0, 1, or 2. However, since we are considering the second excited state specifically, l would be equal to 2. On the other hand, a helium ion in the second excited state would also have n = 3, and thus, its l could also be 0, 1, or 2. Again, for the second excited state, l would be 2.
