High School

At the gym, Jasper was able to bench press 224 pounds, which was [tex]\frac{7}{8}[/tex] of the weight that Balin was able to bench press. Which shows the correct equation and value of [tex]x[/tex], the weight that Balin could bench press?

A. [tex]\frac{7}{8} x = 224; \, x = 196[/tex] pounds

B. [tex]\frac{7}{8} x = 224; \, x = 256[/tex] pounds

C. [tex]\frac{7}{8} = \frac{x}{224}; \, x = 196[/tex] pounds

D. [tex]\frac{7}{8} = \frac{x}{224}; \, x = 256[/tex] pounds

Answer :

To solve this problem, we are given that Jasper was able to bench press 224 pounds, which was [tex]\(\frac{7}{8}\)[/tex] of the weight that Balin could bench press. We need to find the equation and the value of [tex]\(x\)[/tex], representing the weight that Balin could bench press.

Let's break it down step by step:

1. Understand the Relationship:
- We know [tex]\(\frac{7}{8}\)[/tex] of Balin's bench press weight equals Jasper's bench press weight of 224 pounds.

2. Set Up the Equation:
- The equation for this scenario is [tex]\(\frac{7}{8} \times x = 224\)[/tex], where [tex]\(x\)[/tex] is the weight Balin could bench press.

3. Solve for [tex]\(x\)[/tex]:
- To find [tex]\(x\)[/tex], we need to isolate it in the equation. We can do this by multiplying both sides by the reciprocal of [tex]\(\frac{7}{8}\)[/tex], which is [tex]\(\frac{8}{7}\)[/tex].

4. Calculate:
[tex]\[
x = 224 \times \frac{8}{7}
\][/tex]

5. Simplify:
- Perform the multiplication:
[tex]\[
x = \frac{224 \times 8}{7} = \frac{1792}{7} = 256
\][/tex]

So, the correct equation and value of [tex]\(x\)[/tex] are [tex]\((\frac{7}{8})x = 224\)[/tex], and [tex]\(x = 256\)[/tex] pounds.

The correct choice from the options given would be:
[tex]\(\frac{7}{8} x = 224 ; x = 256\)[/tex] pounds.