High School

How many grams of ethanol (C2H60) are required to produce 1,000

kJ during boiling? The heat of vaporization of ethanol is 38.6 kJ /

mole. Round to a whole number

Answer :

16.95g is the mass of ethanol (C2H60) that are required to produce 1,000 kJ during boiling? The heat of vaporization of ethanol is 38.6 kJ / mole.

The most fundamental characteristic of matter is mass, which is one of the basic quantities in physics. Mass is a term used to describe how much matter is there in a body. The kilogramme (kg) is the international standard of mass. A nuclear reaction, for instance, results in the total weight of the substance being reduced as a tiny quantity of matter is transformed into a very large amount of energy.

moles of ethanol = 38.6/ 1,000=0.368moles

molecular weight of ethanol =46.07g/mol

mass = 0.368×46.07

= 16.95g

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