High School

At the Fisher Farm, the weights of zucchini squash are normally distributed. Which standardized weight represents the 5th percentile?

A. -1.64
B. -1.28
C. 1.28
D. 1.64

Answer :

Final answer:

The standardized weight representing the 5th percentile in a normally distributed set of data is a Z-score of -1.64, which corresponds to option A.

Explanation:

The standardized weight that represents the 5th percentile for a normally distributed set of data can be found by looking at a standard normal distribution table or using a Z-score calculator.

The 5th percentile falls in the left tail of the normal distribution. This is equivalent to a Z-score that marks the point below which 5% of the data fall.

The correct Z-score that corresponds to the 5th percentile of a normal distribution is -1.64.

Therefore, the answer to your question is A. -1.64.

This Z-score indicates that the weight of the zucchini squash that corresponds to the 5th percentile is 1.64 standard deviations below the mean weight of the zucchini squash at Fisher Farm.