Answer :
Final answer:
At a substrate concentration of 5.00 mM, with a Vmax of 4.50 mM·s−1 and a Km of 5.00 mM, the reaction velocity (v0) of the enzyme-catalyzed reaction is calculated to be 2.25 mM·s−1 using the Michaelis-Menten equation.
Explanation:
The question asked involves calculating the reaction velocity, v0, for an enzyme-catalyzed reaction at a given substrate concentration using the Michaelis-Menten equation. The Michaelis-Menten equation is v = (Vmax [S]) / (Km + [S]), where Vmax is the maximum rate of the reaction, Km is the Michaelis constant, and [S] is the substrate concentration. For a substrate concentration of 5.00 mM, with Vmax = 4.50 mM·s−1 and Km = 5.00 mM, the reaction velocity, v0, can be calculated as follows: v = (4.50 mM·s−1 × 5.00 mM) / (5.00 mM + 5.00 mM) = 2.25 mM·s−1. Hence, at a substrate concentration of 5.00 mM, the reaction velocity is 2.25 mM·s−1.
