Answer :
The initial concentrations of N2 and H2 in a 4.00 L flask, given 6.00 moles of each gas, are both 1.50 M (molar).
N2 and H2 can be calculated as follows:
For N2: $rac{6.00 moles}{4.00 L}$ = 1.50 M
For H2: $rac{6.00 moles}{4.00 L}$ = 1.50 M
To determine the initial concentrations of N2 and H2 in a 4.00 L flask, one must use the concept of molarity, which is moles per liter (mol/L). The initial moles of N2 and H2 are both given as 6.00 moles.
Therefore, the initial concentration of N2 is calculated by dividing the number of moles by the volume of the flask: concentration of N2 = 6.00 moles of N2/4.00 L = 1.50 M (molar). Similarly, the initial concentration of H2 is also concentration of H2 = 6.00 moles of H2/4.00 L = 1.50 M (molar).
