Answer :
Final answer:
The average power exerted by the weightlifter when lifting 240 kg to a height of 2.5 m in 3 seconds is 1960 W, which is choice A in the options provided.
Explanation:
The question concerns the calculation of average power exerted by a weightlifter when lifting a mass to a certain height over a time period, which is a classic problem in physics associated with work and power. To determine the average power, we use the formula P = (m × g × h) / t, where m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s²), h is the height the object is lifted, and t is the time taken to lift the object. In this case, the mass (m) is 240 kg, the height (h) is 2.5 m, and the time (t) is 3 seconds. So the work done W is m × g × h = 240 kg × 9.8 m/s² × 2.5 m = 5880 Joules. The power P is then W / t = 5880 J / 3 s = 1960 W, which corresponds to choice A)
