Answer :
When the length of a violin string is shortened to one-eighth of its original length, the frequency of the string's note increases to eight times its original frequency. So, a string originally tuned to a frequency of 490 Hz will produce a frequency of 3920 Hz when shortened to one-eighth of its length.
The fundamental frequency of a string on a musical instrument such as a violin changes when the length of the string is altered by, for example, placing a finger down on the string.
The frequency is inversely proportional to the length of the string.
In this case, the violinist is shortening the string to one-eighth its original length.
So, the frequency of the string when played will be 490 Hz multiplied by 8 which equals 3920 Hz.
This can be explained by the physics principle that the frequency of a vibrating string is given by the speed of the waves on the string divided by the wavelength of the waves.
Here, halving the length of the string doubles the fundamental frequency, shortening it to one-third of its length triples the frequency, and so on.
So, shortening the string to one-eighth of its length multiplies the frequency by 8.
Remember, this only applies when the tension in the string and its linear density remain constant. When a string is plucked on a string instrument, the sound produced is called a note.
Each note corresponds to a certain frequency.
Therefore, different lengths of the string will produce different notes due to the changing frequencies.
Learn more about String Frequency here:
https://brainly.com/question/32824104
#SPJ11
