Answer :
Final answer:
To find the volume of a 1.55 m potassium hydroxide solution containing 53.0 g of solute, convert the solute mass to moles, apply the rearranged molarity formula, and convert your result from liters to milliliters to get approximately 609 ml.
Explanation:
To calculate the volume in milliliters of a 1.55 m potassium hydroxide solution that contains 53.0 g of solute, you first need to determine the number of moles the solute represents. Potassium hydroxide (KOH) has a molar mass of approximately 56.11 g/mol. Therefore, 53.0 g of KOH is approximately 0.944 mol of KOH.
Remembering that molarity (M) is the number of moles of solute per liter of solution (mol/L), we can rearrange the formula for molarity into the following: volume (L) = moles of solute / M. Plugging the values we have into this equation, we get volume (L) = 0.944 mol / 1.55 M. This gives a volume of approximately 0.609 liters.
Because the question asks for the answer in milliliters, we then convert liters to milliliters by multiplying by 1000, resulting in a final volume of approximately 609 milliliters of 1.55 M potassium hydroxide solution that contains 53.0 g KOH.
Learn more about Molarity Calculations here:
https://brainly.com/question/33057890
#SPJ11
