High School

A tire is rotating 900 times per minute. Through how many degrees does a point on the edge of the tire move in [tex]\frac{1}{5}[/tex] of a second?

The point on the edge of the tire rotates _____ degrees in [tex]\frac{1}{5}[/tex] of a second.

Answer :

Final answer:

A point on the edge of the tire rotates 6 degrees in 1/5 second.

Explanation:

To find out how many degrees a point on the edge of a rotating tire moves in 1/5 second, we need to calculate the angle covered by one complete revolution of the tire and then find the proportion of that angle covered in 1/5 second.

First, we know that one revolution is equal to 360 degrees or 2 radians. So, the angle covered by one complete revolution is 360 degrees or 2 radians.

Next, we need to find the proportion of that angle covered in 1/5 second. Since the tire is rotating 900 times per minute, that means it rotates at a speed of 900/60 = 15 rotations per second. Thus, in 1 second, the tire covers an angle of 15 * 2 = 30 radians. Therefore, in 1/5 second, the tire covers an angle of 30 * 1/5 = 6 radians. So, a point on the edge of the tire rotates 6 degrees in 1/5 second.

Learn more about complete revolution here:

https://brainly.com/question/36892815

#SPJ11