High School

A three-phase fully controlled rectifier is operated from a 220V, 50Hz source and a load resistance. If it is required to obtain an average output voltage of 70% of the maximum possible output voltage, calculate the firing angle of the switching devices.

(b) State the function of Buck and Boost Choppers.

Answer :

The average output voltage can be controlled, allowing for voltage regulation in various applications.

To calculate the firing angle of the switching devices in a three-phase fully controlled rectifier, we need to consider the relationship between the average output voltage and the firing angle.

The average output voltage of a three-phase fully controlled rectifier can be calculated using the formula:

V_avg = (3√2 / π) * Vm * cos(α)

where:

V_avg is the average output voltage,

Vm is the maximum possible output voltage,

α is the firing angle of the switching devices.

Source voltage (Vm) = 220V

Frequency (f) = 50Hz

Load resistance = R

We know that the maximum possible output voltage is given by:

Vm = √2 * V_source

Vm = √2 * 220V

Next, we are given that the required average output voltage is 70% of the maximum possible output voltage:

V_avg = 0.7 * Vm

Now, we can rearrange the formula to solve for the firing angle (α):

α = cos^(-1)((V_avg * π) / (3√2 * Vm))

Substitute the given values and calculate the firing angle (α).

Regarding the second part of your question:

b) The function of a Buck and Boost Chopper is to control the output voltage by adjusting the duty cycle of the chopper. A Buck Chopper is used to step down the output voltage, while a Boost Chopper is used to step up the output voltage. By varying the duty cycle (on-off time ratio) of the chopper, the average output voltage can be controlled, allowing for voltage regulation in various applications.

To know more about Frequency, visit:

https://brainly.com/question/29739263

#SPJ11

(a) The firing angle of the switching devices is 65.56°

(b) The Buck chopper (step-down chopper) is used for decreasing the output voltage of a DC source.

The boost chopper (step-up chopper) is used for increasing the output voltage of a DC source.

(a) Calculation of firing angle of the switching devices:

Given, V_s = 220 V, f = 50 Hz, R_L = load resistance, V_o = 0.7 (maximum possible output voltage)

Let's first find the maximum possible output voltage;

The peak voltage of a 220 Vrms sinusoidal waveform is given as follows:

[tex]V_p = \sqrt{2 \times V_rms}\\= \sqrt{2 \times 220} \\= 311.13[/tex]

Vmaximum possible output voltage, [tex]V_o = V_p/\pi\\= 311.13/\pi\\ = 99.04 V[/tex]

For a fully controlled rectifier, the output voltage is given as: [tex]V_o = (2\sqrt2/\pi) \times V_s \cos(a)[/tex]

Therefore, [tex]\cos(a) = V_o / [(2\sqrt2/\pi) \times V_s]\\= (0.7 \times 99.04) / [(2\sqrt2/\pi) \times 220]\\= 0.429[/tex]

Therefore, [tex]a = \cos^{-1}(0.429)= 65.56\textdegree[/tex]

Thus, the firing angle of the switching devices is 65.56°

(b) Function of Buck and Boost Chopper:

The Buck chopper (step-down chopper) is used for decreasing the output voltage of a DC source. This is done by turning on and off the switching device in a controlled manner so that the average value of the voltage across the load decreases.

The boost chopper (step-up chopper) is used for increasing the output voltage of a DC source. This is done by turning on and off the switching device in a controlled manner so that the average value of the voltage across the load increases.

To know more about Buck chopper, visit:

https://brainly.com/question/14866329

#SPJ11