Answer :
Sure, let's find out how much juice Mr. Maners has in total by adding the amounts of the different juices together.
1. Identify the fractions:
- Orange juice: [tex]\( \frac{2}{5} \)[/tex]
- Pineapple juice: [tex]\( \frac{1}{4} \)[/tex]
- Mango juice: [tex]\( \frac{3}{10} \)[/tex]
2. Find a common denominator:
To add these fractions, we need a common denominator. Let's choose 20, which is a common multiple of 5, 4, and 10.
3. Convert each fraction to have the common denominator of 20:
- For orange juice:
[tex]\( \frac{2}{5} = \frac{2 \times 4}{5 \times 4} = \frac{8}{20} \)[/tex]
- For pineapple juice:
[tex]\( \frac{1}{4} = \frac{1 \times 5}{4 \times 5} = \frac{5}{20} \)[/tex]
- For mango juice:
[tex]\( \frac{3}{10} = \frac{3 \times 2}{10 \times 2} = \frac{6}{20} \)[/tex]
4. Add the fractions:
- Combine the numerators:
[tex]\( \frac{8}{20} + \frac{5}{20} + \frac{6}{20} = \frac{8 + 5 + 6}{20} = \frac{19}{20} \)[/tex]
5. Conclusion:
- The total amount of juice Mr. Maners has is [tex]\( \frac{19}{20} \)[/tex] of a gallon.
Therefore, the correct answer is [tex]\( \frac{19}{20} \)[/tex].
1. Identify the fractions:
- Orange juice: [tex]\( \frac{2}{5} \)[/tex]
- Pineapple juice: [tex]\( \frac{1}{4} \)[/tex]
- Mango juice: [tex]\( \frac{3}{10} \)[/tex]
2. Find a common denominator:
To add these fractions, we need a common denominator. Let's choose 20, which is a common multiple of 5, 4, and 10.
3. Convert each fraction to have the common denominator of 20:
- For orange juice:
[tex]\( \frac{2}{5} = \frac{2 \times 4}{5 \times 4} = \frac{8}{20} \)[/tex]
- For pineapple juice:
[tex]\( \frac{1}{4} = \frac{1 \times 5}{4 \times 5} = \frac{5}{20} \)[/tex]
- For mango juice:
[tex]\( \frac{3}{10} = \frac{3 \times 2}{10 \times 2} = \frac{6}{20} \)[/tex]
4. Add the fractions:
- Combine the numerators:
[tex]\( \frac{8}{20} + \frac{5}{20} + \frac{6}{20} = \frac{8 + 5 + 6}{20} = \frac{19}{20} \)[/tex]
5. Conclusion:
- The total amount of juice Mr. Maners has is [tex]\( \frac{19}{20} \)[/tex] of a gallon.
Therefore, the correct answer is [tex]\( \frac{19}{20} \)[/tex].
