Answer :
Final answer:
To calculate the diagonal length of a suitcase measuring 22 inches by 16 inches, use the Pythagorean theorem. The result is approximately 27.2 inches, which is about 2.27 feet - when rounded, the diagonal length is 2 feet.
Explanation:
To find the diagonal length of a suitcase that measures 22 inches long and 16 inches high, we will use the Pythagorean theorem, which is applicable for right-angled triangles. This theorem states that the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. In this case, the length and height of the suitcase are the two sides, and the diagonal is the hypotenuse we are trying to find.
We can express the calculation as follows: Diagonal length2 = Length2 + Height2
Diagonal length2 = 222 + 162
Diagonal length2 = 484 + 256
Diagonal length2 = 740
Therefore, the diagonal length is the square root of 740, which is approximately 27.2 inches. To convert inches to feet, we divide by 12, giving us approximately 2.27 feet. To the nearest foot, the diagonal length of the suitcase is approximately 2 feet.
Use the Pthygorean Therorem.
a^2+b^2=c^2
16^2+22^2=c^2
256+484=c^2
c=27.2
The length of the diagonal is 27 feet.
a^2+b^2=c^2
16^2+22^2=c^2
256+484=c^2
c=27.2
The length of the diagonal is 27 feet.
