Answer :
Final answer:
To find the 95% confidence interval of the mean score for all bowlers, use the formula: mean ± (z-score * (standard deviation / square root of sample size)). The correct answer is (A) 186 ± 1.96 * 6.
Explanation:
To find the 95% confidence interval of the mean score for all bowlers, we need to use the formula: mean ± (z-score * (standard deviation / square root of sample size)).
The z-score for a 95% confidence level is 1.96.
Substituting the given values, the 95% confidence interval is: 186 ± (1.96 * (6 / √40)).
Simplifying the expression gives us the answer: 186 ± 1.55.
Therefore, the correct answer is (A) 186 ± 1.96 * 6.
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