Answer :
Final answer:
The acceleration of the plane during takeoff at max thrust is approximately 1.18 m/s^2.
Explanation:
To find the acceleration of the plane during takeoff at max thrust, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration: F = m * a.
In this case, the force (thrust) is given as 55,000 N on each of the 2 engines, so the total force is 2 * 55,000 N = 110,000 N. The mass of the plane is given as 93,000 kg.
Plugging these values into the equation, we get: 110,000 N = 93,000 kg * a. Solving for acceleration, we find that the acceleration of the plane during takeoff at max thrust is approximately 1.18 m/s^2.
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