A scuba diver descended [tex]19 \frac{5}{12}[/tex] feet below sea level. Then, he descended another [tex]3 \frac{3}{5}[/tex] feet. Which of the following is true about the scuba diver after both descents?

A. The location of the scuba diver in relation to sea level was [tex]-23 \frac{1}{60}[/tex] feet.

B. The location of the scuba diver in relation to sea level was [tex]15 \frac{49}{60}[/tex] feet.

C. The location of the scuba diver in relation to sea level was [tex]23 \frac{1}{60}[/tex] feet.

D. The location of the scuba diver in relation to sea level was [tex]-15 \frac{49}{60}[/tex] feet.

The correct statement about the scuba diver after both descents is the scuba diver descended 19 and 5/12 feet below sea level and then descended another 3 and 3/5 feet. Option A is correct.

To find the total depth below sea level, we need to add these two depths.

19 and 5/12 + 3 and 3/5 = 22 and 8/12 + 3 and 6/10 = 26 and 2/10

However, the question asks for the scuba diver's location in relation to sea level, not the total depth below sea level. To find this, we need to subtract the total depth below sea level from sea level.

Sea level - 26 and 2/10 = -23 and 1/60

Therefore, the location of the scuba diver in relation to sea level was –23 and 1/60 feet. Option A is the correct answer.

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